There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

Effort = Sf + (Load/(2 x pi x (R/p) x Se))

where:
p = pitch of the screw
Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
R = radius of the lead screw


This formula is based on the "law of the machine"

The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

Example:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 13 = .08 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
Effort = 5 N + (90 N / (15.7))
Effort = 5 N + (5.73 N)
Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

With a bit of algebra, the formula can be rewritten to find the load:

Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

Another formula that does not consider friction at all:

Effort = (Load x p) / (2 x pi x R)

Lets see if we get similar results:

Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

Example for a 10 TPI 5 start (2 turns per inch) lead screw:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 2 = .5 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
Effort = 5 N + (90 N / (6.28 x 2 x .2))
Effort = 5 N + (90 N / (2.512))
Effort = 5 N + (35.83 N)
Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

Customer Response:
thank you so much

Additional Information:


Additional Information:


Additional Information:
how do i calculate torque of stepper motor if lead screw coupled to motor shaft and load applied by lead screw on plate is 100 kg by vertically

Additional Information:
Pls


Additional Information:
1m 16mmdiameter ball screws calculations


Additional Information:
What is the max load that 2 NEMA 17 stepper motors (spaced 2 feet apart, both will be pushing up on the same gantry) can lift while using a rod with the following specifications T8 OD 8mm Pitch 2mm Lead 4mm for each motor.

Additional Information:


Additional Information:
1

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I need the calculation to determine the stepper motor torque to find the load that it can withstand in horizontal position using a lead screw at 1/2" diameter with 13 TPI.

There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

Effort = Sf + (Load/(2 x pi x (R/p) x Se))

where:
p = pitch of the screw
Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
R = radius of the lead screw


This formula is based on the "law of the machine"

The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

Example:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 13 = .08 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
Effort = 5 N + (90 N / (15.7))
Effort = 5 N + (5.73 N)
Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

With a bit of algebra, the formula can be rewritten to find the load:

Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

Another formula that does not consider friction at all:

Effort = (Load x p) / (2 x pi x R)

Lets see if we get similar results:

Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

Example for a 10 TPI 5 start (2 turns per inch) lead screw:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 2 = .5 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
Effort = 5 N + (90 N / (6.28 x 2 x .2))
Effort = 5 N + (90 N / (2.512))
Effort = 5 N + (35.83 N)
Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

Customer Response:
thank you so much

Additional Information:


Additional Information:


Additional Information:
how do i calculate torque of stepper motor if lead screw coupled to motor shaft and load applied by lead screw on plate is 100 kg by vertically

Additional Information:
Pls


Additional Information:
1m 16mmdiameter ball screws calculations


Additional Information:
What is the max load that 2 NEMA 17 stepper motors (spaced 2 feet apart, both will be pushing up on the same gantry) can lift while using a rod with the following specifications T8 OD 8mm Pitch 2mm Lead 4mm for each motor.

Additional Information:


Additional Information:
1

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thank you for the reply. I would be really good to know the calculation. The lead screw is 1/2" diameter with 13 TPI. Please provide the calculation for determing the maximum weight motor can handle on Z-axis on book build cnc. And one more question. If I am cutting 18mm MDF with 6mm cutting bit (so 6mm pass), what can be the maximum speed rate of cutting and spindle speed of router? thank you

It generally does not matter if it is longer at the other end as long as the lead screw provides the desired travel for that axis. The lead screw will only need to be long enough for the travel, plus any structure and lead-nut positioning.

For example:
- The motor that will turn the lead screw will need to be mounted at some position (generally at one end of the axis). In many cases, this positioning will be mounted where some of the lead screw will not be used (the lead nut will not be able to moved close to the coupling of the lead screw to the motor shaft). Add some of the length of the lead screw to be inserted into the coupling.

- If the lead screw will contain bearings at either end of the travel, that portion of the mechanical assembly will need to be considered in the lead screw length.

- The lead-nut will need to be mounted in a position on a structural member of the part that is to move. The distance from the part of the structure that will extend closest to the motor will have some distance to the position of the lead nut. This distance will need to be added to the lead screw length.

Add these discrepancies to the length of the lead screw and the travel length and you will have the final length.

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How to determine lead screw length needed. My Thomson 1 1:4 rails are 60 inches long roughly for the router I’m building. I know I have to have it long enough to couple up with the stepper motor of course but does it matter if it’s a little long on the other end

The settings that will have to be change will be your steps per inch in motor tuning (mach 3), or settings/axes(planetCNC). But we do not have the actual numbers/specs that will fit your 10 TPI 5 start lead screw, here is a tutorial video which explains how to get the exact numbers you need! (

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On the Book Build: I'm changing the 13TPI 1/2" lead screw with the 1/2" 10 TPI Acme screw with the anti backlash nut. This is for the Z axis only. What should I know about installing it and what are the numbers I need to plug into the motor tuning area.

This gear should work with this motor. The shaft on the 651ozin motor is 3/8"

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I am working with a Spur gear that has a 15 tooth 3/8 bore/ 3/8 wide....is the 651ozin stepper motor compatible with this or do I need to get a different motor

Modifying the Z-axis to accommodate a larger motor will be a worth while task and is possible, however we have not calibrated the z-axis therefore using the 1600 Steps-per inch in the motor tuning on our machine in our shop. We have not noticed any significant depth increments from not calibrating the z-axis but only from zeroing the z axis too close to the material. Also in your design did you specify the actual depth and the length of tool (end mill/ bit) that you are using?

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I bought a Blacktoe 2 x 8 three years ago and have always had a problem with the Zid axis. No matter how tightly I've calibrated the axis it always cuts to deep. Can I put a larger Stepper motor on Z-axis using the same motion electronics that came with the original machine.

Yes, if you need a replacement part on your machine please call us at 281-815-7701.

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I have a blacktooth laser engraver. The Y Axis stepper motor needs to be replaced. Can you please provide me with the information I would need to replace this motor.

Here is the formula for steps/inch (steps per inch)

Steps = how many steps for a full ration of the motor = standard motor steps x number of microsteps for each step
Standard motor steps for our stepping motors is 200 steps per revolution.
Microsteps are selected on the driver and are shown as full, 1/2, 1/4, 1/8, 1/16, 1/32 etc... Use the denominator for the number of microsteps per step.

Inches = how far the travel is for one full rotation of the motor. For the 1/2" - 13 TPI (threads per inch), the travel length will be 1"/13 or .076923". So, for one revolution of the motor, the travel distance will be .076923 inches.

So, the steps = 200 * microsteps, let's make this 1/4 just for the formula.
The inches will be .076923. Plug those into the formula:
Steps / inch = (200 * 4) / .076923 This can also be written as:
200 * 4 / (1 / 13) = 10,400



Additional Information:

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I am asking what to set my steps per using your kit stepper motors and a 1/2"x13 lead screw with Mach3

There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

Effort = Sf + (Load/(2 x pi x (R/p) x Se))

where:
p = pitch of the screw
Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
R = radius of the lead screw


This formula is based on the "law of the machine"

The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

Example:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 13 = .08 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
Effort = 5 N + (90 N / (15.7))
Effort = 5 N + (5.73 N)
Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

With a bit of algebra, the formula can be rewritten to find the load:

Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

Another formula that does not consider friction at all:

Effort = (Load x p) / (2 x pi x R)

Lets see if we get similar results:

Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

Example for a 10 TPI 5 start (2 turns per inch) lead screw:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 2 = .5 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
Effort = 5 N + (90 N / (6.28 x 2 x .2))
Effort = 5 N + (90 N / (2.512))
Effort = 5 N + (35.83 N)
Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

Customer Response:
thank you so much

Additional Information:


Additional Information:


Additional Information:
how do i calculate torque of stepper motor if lead screw coupled to motor shaft and load applied by lead screw on plate is 100 kg by vertically

Additional Information:
Pls


Additional Information:
1m 16mmdiameter ball screws calculations


Additional Information:
What is the max load that 2 NEMA 17 stepper motors (spaced 2 feet apart, both will be pushing up on the same gantry) can lift while using a rod with the following specifications T8 OD 8mm Pitch 2mm Lead 4mm for each motor.

Additional Information:


Additional Information:
1

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HOW DO I DETERMINE THE AMOUNT OF SCREW WEIGTH THAT MY MOTOR CAN HANDLE

Thanks for the question. The blackToe z-axis motor is a NEMA 24 425 oz-in stepping motor and the next step up is a NEMA 34 651 oz-in motor located here: https://buildyourcnc.com/item/electronicsAndMotors-nema34-651ozin


To make it work on the blackToe CNC machine, you would need to fabricate a new mount and the top bearing mount, or request us to fabricate it for you by calling the office.

Curious, why the need to increase the size? If the motor is having a difficult time, there may be a deeper mechanical issue at play. One issue you may have is that the bearings are needing shim washers to separate the inner and outer races. If the two races are rubbing against the coupling or collar, the bearing may be difficult to turn under the weight of the assembly. If there is too much friction between the anti-backlash nut and the lead screw, you can add some 2-in-1 oil, or other similar lubricant.

Thank you for using our Customer Service Live. Patrick often answers these questions. We prefer this system over email as these questions will benefit others.

If you have additional questions or need more explanation relating to this question, please add to this answer.

User response:
I have added the shim washer between the bearing and coupling and have always used a light oil on the lead screw. I halved the acceleration on the Z-axis. Then I re-ran a topo that took two hours on the finish pass. No change in my results - the Z-axis slowly dropped until when the program finished and everything went back to the start point, the Z axis was lower by 0.378 inches than when it started at 0.800 above the surface.

Any suggestions would be appreciated. Maybe I need more shim washers in the assembly between all the bearing surfaces?

buildyourcnc response:
Before you add a larger motor, check these first:

1. take the motor off by remove only the motor screws and removing the motor as well as the coupling half that is secured to the motor shaft.

2. Turn the lead screw by hand. This will still be connected to the z-axis assembly by the anti-backlash nut, so you will feel the resistance in the upward motion of the z-axis. Does it feel relatively easy to turn, or very difficult?

3. If the resistance is relatively normal with respect to gravity and normal friction between the anti-backlash nut and the screw, then you may want to half the velocity as well on the z-axis motor tuning, and even reduce the acceleration a bit more. Doing topographical layouts should not require fast z-axis motor travel. Be careful not to lower the z-axis acceleration if you are using constant velocity as this can make the topo "too smooth" where there may be features such as cliffs present. If you need to lower acceleration drastically, then use exact stop rather than constant velocity.

Another gotcha that may be causing this phenomenon is motor cable/wire chafing. We had this same issue crop up where two wires were shorting only at a specific position because the wires moved just enough to cause these wires to connect. This was caused by a zip tie. Zip ties have a very sharp edge that can cut the insulation of the wire. A hint of this problem is if this phenomenon is only present after working successfully with the machine for a greater period of time.

Use response:
I bought a new lead screw, bearings, antibacklash nut, and shim washers (WHICH NEED TO BE IN YOUR ONLINE CATALOG) and installed them. (Like another commentor on this site, my lead screw wouldn't go through the bearings. Simple solution was to chuck it into my drill press and 400 grit smooth it until a snug fit was had. Lowest RPM.)

Anyhow, I ran another Topo yesterday and got the same results. The wires are not frayed, the acceleration has been halved, the speed reduced to a crawl. When testing manually, twisting the Z axis up was very hard to do compared to lowering it.

I have thought about a counterbalance of some type, but that introduces lots of other problems.

Anything you can thing of will certainly help.

I can send pictures, etc.

Thanks!

Buildyourcnc response
What router/spindle do you have installed?

User response:
The one you sold me - 110 V, 1.5KW water cooled.

User response:
This problem of the z axis drift has been evident since I first started using the machine a couple of years ago. Lithophanes, stipples, topographic and other heavy z axis users have been particularly bad. It is to the point that I am turning away opportunities for lack of capability.

Buildyourcnc response:
I think all options may be exhausted. We will design a new mount that holds a large motor. Please give us a call so we can arrange to send that out to you.

We just determined that the existing mount need to be adjusted by about one millimeter for the main mounting hoes for the larger NEMA 34 motor to fit. The overall mount will look the same but the outside hole spacing will be adjusted by a very small amount to match the larger motor mounting holes. This new adjustment will be included with all new machines. We will send you the new mount (consisting of two structural pieces) and the longer screws that will be needed to extend to fit the motor frame thickness.

Additional Information:


Additional Information:
They didn't send the longer screws, nor the new required coupling, but I finally got it together and it works just fine. It returns to precise Z zero every time.

But the motor runs pretty hot because I think it should be run at a higher voltage than the current power supply provides.

Any new sales of Blacktoe 4.1 should include this modification.

Cheers.

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What would I need to purchase to increase the Z axis stepper motor up one size from the one that comes with the Blacktoe 4.1 with computer? I can't get Patrick to answer e-mails, so I'll try here.

a 2' (24 inches) diameter workpiece for a 2'x8' machine may be a bit too much for an overhang. I would recommend the 4'x8' that can house a 4th axis in a cavity within the limits of the machine for a 24-inch part. If you need the rotary axis on the side of the machine, I can design a machine that would work.

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[790] Is there a way to build a 2x8 flat cnc with a 4 th axis on the side so I can do 24” diameter objects. Or have the z axis that tall

Book build (scratch build), feedrates and recommendation.

Using standard allthread will provide around 20-30 ipm using 36 volts. Although it allows for a working CNC machine, the RPM of the spindle/router will need to spin at the lowest setting to provide the beat efficiency and life for the end mill at 1/4" cut diameter and higher. The speeds may be fine for smaller end mills.

If you would like faster speeds, you should change the lead screws on the CNC machine to the 1/2" 5 start 10 TPI which translates to 2 turns per inch which means, the stepping motor will not need to turn as fast to produce faster motion. That is to say, the stepping motor will only need to turn two revolutions for the machine to travel one inch and with the allthread, the stepping motor will need to turn 13 times to reach one inch.

Link to the lead screw and other mechanical parts needed:
https://www.buildyourcnc.com/CNCMachineMechanicalParts.aspx

To change the lead screws you will need (for each axis):

1. The lead screw for that axis.
2. Two 1/2" collars to keep the lead screw axially stable.
3. One Antibacklash nut.

Additional Information:
20

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Since I am using normal all-thread lead screw 13 TPI 1/2" for the book build cnc, what can be the maximum feed rate of machine and how can I change the mechanical setup in mach 3? I am using 1/4" steel carbile endmill with 2 flutes and router is 2 HP with variable speed

Yes. We will make sure the lead screw is cut to those dimensions. 53/30/13

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I ordered 96 inches of the 1/2 inch 10 tpi drive screw. I need it in 3 pieces. 53 inches, 30 inches, and 13 inches. Please let me know if that can happen. Thankyou

Decreasing the speed of acceleration in the cutter? Meaning of your router/spindle?, To modify the speed of a router will be going to the router itself and modifying the speed, but if a spindle is being used modifying it will be done either manually in the VFD (VFD Setup:
Change PD001 to '0' (source of run commands)
Change PD003 to 300 (main frequency - Hz)
Change PD004 to 300 (base frequency - Hz)
Change PD005 to 400 (max operating frequency - Hz)
Change PD006 to 2.5 (intermediate frequency - Hz)
Change PD008 to 220 (max voltage - V)
Change PD009 to 15 (intermediate voltage - V)
Change PD010 to 8 (minimum voltage - V)
Change PD011 to 100 (frequency lower limit - Hz)
Change PD142 to 7 (rated motor current - Amps)
Change PD143 to 2 (motor pole number)
Change PD144 to 3000 (rated motor revolution))<- make sure these are your settings in the VFD. If the spindle is wired to the breakout board and is working through Mach 3 then the modification will be done in your CamBam/Feed rate settings.

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How can I decrease the rapid acceleration of the cutter from a completed cutting operation to a new location so that the stepper motor will not lose its steps and mess up the machine zero settings? I am using CamBam and Mach3 on my machine with a chain drive. what is the best way to reduce accleration

The settings that will have to be change will be your steps per inch in motor tuning (mach 3), or settings/axes(planetCNC). But we do not have the actual numbers/specs that will fit your 10 TPI 5 start lead screw, here is a tutorial video which explains how to get the exact numbers you need! (

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On the book build machine I changed the Z axis from a 13 tpi lead screw to an acme 10 tpi 5 start lead screw. What numbers do I put into the motor tuneing boxes.

Assumption 1: The "raw data" of 24 mrem on the TLD is the total dose received by the TLD during the 22 days that the TLD was deployed in your office. This means that (1) any TLD reader background signal has been properly subtracted, (2) the signal accumulating in the TLD during any transport or storage time between preparation (annealing) and deployment in your office has been properly subtracted and, (3) the signal accumulating in the TLD during any transport or storage time between removal from your office and processing (reading) has been properly subtracted.

With this assumption, the total dose rate in your office is (24 mrem)/(22 days), or 1.091 mrem per day. The reference background is given as 63 mrem per year which is (63 days)/(365.25 days per year) or 0.172 mrem per day. Thus the average net dose rate to the TLD during the 22 days was (1.091-0.172) = 0.919 mrem per day.

Assumption 2: The net dose rate of 0.919 mrem per day in your office is attributable to the accelerator or other regulated sources under the control of your institution.

Assumption 3: The office occupancy factor of 1/4 attributed in your question to NCRP Report 49 was misread from Table 4. The correct occupancy factor given in NCRP 49 for offices is 1.

Assumption 4: You take 20 business days per year off for vacation and holidays. You work in your office for the remaining 240 days per year.

Assumption 5: All of the accelerator shots occur while you are in your office.

Assumption 6: The average net dose rate of 0.919 mrem per day determined during the 22 days of measurement continues for a year.

Based on the data that you provided and my assumptions, your annual dose received in your office from the accelerator or other regulated sources at your institution is predicted to be (0.919 mrem per day) x (240 work days per year) = 220 mrem.

Tom Gesell, PhD

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HOW CAN I DETERMINE THE DOSE EQUIVALENT (MREM/HR, MREM/WK, MREM/YR) USING RAW DATA FROM A TLD (THERMOLUMINESCENT DOSIMETER) THAT WAS PLACED IN AN OFFICE FOR 22 DAYS?

it is possible to install 2 motors on a single axis but you will require another driver and motor, but wire it directly to the same pins on your breakout board. Also the orientation of your motor since it is opposite side of the original so getting it to move accordingly to the original motor it will need to be orientated correctly. The slight shift could be the cause of the rod not being completely flat where the set screws are suppose to tighten the sprocket to the rod, so sanding it to a flatter surface might fix the shift in directions.
Currently do not have a kit or schematic available.

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My X-axis on the Blacktoe cannot run above ~40 ipm. I've checked all connections,tensions, sprocket locks, etc. All is fine. Can the 425 OZ stepping motor be replaced with a bigger motor, or could a second 425 OZ stepper be added to increase torque?

The KL-4030 is a Keling 3.0 amp stepper motor driver. These are generally pretty robust drivers. You mentioned in the question that it worked for one hour. This sounds like it could be a contact issue with the wiring in the terminals. I would recommend that you check all of the connections. The terminals that are used in these drivers have terminals that are easily used incorrectly.

Make sure to open the terminal all the way using a small screw driver. Then insert the exposed wire into the opening and re-tighten the terminal. Make sure of a good connection by tugging on the wires.

Also, check kthe digital wires that connect from the driver to the control board.

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I have a KL-4030 stepper motor driver that I only have about an hour use on it but seems to be bad already. Has anyone out there had the same problem?

The settings that will have to be change will be your steps per inch in motor tuning (mach 3), or settings/axes(planetCNC). But we do not have the actual numbers/specs that will fit your 10 TPI 5 start lead screw, here is a tutorial video which explains how to get the exact numbers you need! (

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I just changed my X and Y to the ACME 1/2" 5 start lead screw. What are the motor tuning numbers. I have the book built machine.