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Question #: 3447

Question: HOW CAN I KNOW MUCH WEIGHT MY MOTOR CARRY?

Current Solution

There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

Effort = Sf + (Load/(2 x pi x (R/p) x Se))

where:
p = pitch of the screw
Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
R = radius of the lead screw


This formula is based on the "law of the machine"

The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

Example:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 13 = .08 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
Effort = 5 N + (90 N / (15.7))
Effort = 5 N + (5.73 N)
Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

With a bit of algebra, the formula can be rewritten to find the load:

Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

Another formula that does not consider friction at all:

Effort = (Load x p) / (2 x pi x R)

Lets see if we get similar results:

Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

Example for a 10 TPI 5 start (2 turns per inch) lead screw:

Load = 90 N (20.2 lbs)
R = 1 inch since that is the length from the center of the shaft that the motor is rated
p = 1 inch / 2 = .5 inches

Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
Effort = 5 N + (90 N / (6.28 x 2 x .2))
Effort = 5 N + (90 N / (2.512))
Effort = 5 N + (35.83 N)
Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

Customer Response:
thank you so much

Additional Information:


Additional Information:


Additional Information:
how do i calculate torque of stepper motor if lead screw coupled to motor shaft and load applied by lead screw on plate is 100 kg by vertically

Additional Information:
Pls


Additional Information:
1m 16mmdiameter ball screws calculations

Respond:

Other Possible Solutions to this Question

  • how much weight can my stepping motor lift?

    There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

    This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

    Effort = Sf + (Load/(2 x pi x (R/p) x Se))

    where:
    p = pitch of the screw
    Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
    Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
    Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
    R = radius of the lead screw


    This formula is based on the "law of the machine"

    The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

    Example:

    Load = 90 N (20.2 lbs)
    R = 1 inch since that is the length from the center of the shaft that the motor is rated
    p = 1 inch / 13 = .08 inches

    Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
    Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
    Effort = 5 N + (90 N / (15.7))
    Effort = 5 N + (5.73 N)
    Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

    I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

    Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

    With a bit of algebra, the formula can be rewritten to find the load:

    Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

    Another formula that does not consider friction at all:

    Effort = (Load x p) / (2 x pi x R)

    Lets see if we get similar results:

    Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
    Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

    The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

    It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

    Example for a 10 TPI 5 start (2 turns per inch) lead screw:

    Load = 90 N (20.2 lbs)
    R = 1 inch since that is the length from the center of the shaft that the motor is rated
    p = 1 inch / 2 = .5 inches

    Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
    Effort = 5 N + (90 N / (6.28 x 2 x .2))
    Effort = 5 N + (90 N / (2.512))
    Effort = 5 N + (35.83 N)
    Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

    Customer Response:
    thank you so much

    Additional Information:


    Additional Information:


    Additional Information:
    how do i calculate torque of stepper motor if lead screw coupled to motor shaft and load applied by lead screw on plate is 100 kg by vertically

    Additional Information:
    Pls


    Additional Information:
    1m 16mmdiameter ball screws calculations

    Click the link to respond:
    how much weight can my stepping motor lift?

  • I received the electronics for book build cnc machine. I need to know how much weight the z-axis motor can hold since my (craftsman) router seems to be heavy. It is 2HP with variable speed

    The motor is helped by the mechanical leverage of the screw. The 425 oz-in motors that are included in the standard electronics combo has very high torque for that type of machine. You will have no problem using that motor for the book machine.

    We use that motor for very heavy spindles on the blackToe and blackFoot CNC Machine kits.

    You will need to do the mechanical leverage calculation along with the torque of the motor to determine the actual weight it will lift. The calculation will need to consider the type and pitch of the screw and it would also consider the gravity constant of 9.8 m/s/s.

    If you need me to determine this formula and work out the calculation based on the screw you are using, please let me know.

    Additional Information:
    thank you for the reply. I would be really good to know the calculation. The lead screw is 1/2" diameter with 13 TPI. Please provide the calculation. And one more question. If I am cutting 18mm MDF with 6mm cutting bit (so 6mm pass), what can be the maximum speed rate of cutting and spindle speed of router?
    thank you

    Click the link to respond:
    I received the electronics for book build cnc machine. I need to know how much weight the z-axis motor can hold since my (craftsman) router seems to be heavy. It is 2HP with variable speed

  • can my stepper motor lift the weight of my router?

    There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

    This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

    Effort = Sf + (Load/(2 x pi x (R/p) x Se))

    where:
    p = pitch of the screw
    Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
    Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
    Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
    R = radius of the lead screw


    This formula is based on the "law of the machine"

    The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

    Example:

    Load = 90 N (20.2 lbs)
    R = 1 inch since that is the length from the center of the shaft that the motor is rated
    p = 1 inch / 13 = .08 inches

    Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
    Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
    Effort = 5 N + (90 N / (15.7))
    Effort = 5 N + (5.73 N)
    Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

    I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

    Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

    With a bit of algebra, the formula can be rewritten to find the load:

    Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

    Another formula that does not consider friction at all:

    Effort = (Load x p) / (2 x pi x R)

    Lets see if we get similar results:

    Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
    Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

    The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

    It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

    Example for a 10 TPI 5 start (2 turns per inch) lead screw:

    Load = 90 N (20.2 lbs)
    R = 1 inch since that is the length from the center of the shaft that the motor is rated
    p = 1 inch / 2 = .5 inches

    Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
    Effort = 5 N + (90 N / (6.28 x 2 x .2))
    Effort = 5 N + (90 N / (2.512))
    Effort = 5 N + (35.83 N)
    Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

    Customer Response:
    thank you so much

    Additional Information:


    Additional Information:


    Additional Information:
    how do i calculate torque of stepper motor if lead screw coupled to motor shaft and load applied by lead screw on plate is 100 kg by vertically

    Additional Information:
    Pls


    Additional Information:
    1m 16mmdiameter ball screws calculations

    Click the link to respond:
    can my stepper motor lift the weight of my router?

  • What maximum weight will my motor torque be able to lift? Effort = Sf + (Load/(2 x pi x (R/p) x Se)) In this formula, is Sf (static force) include gravity? how much usually is static force? can you please give one example to calculate max. weight Z-axis can carry?

    There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

    This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

    Effort = Sf + (Load/(2 x pi x (R/p) x Se))

    where:
    p = pitch of the screw
    Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
    Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
    Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
    R = radius of the lead screw


    This formula is based on the "law of the machine"

    The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

    Example:

    Load = 90 N (20.2 lbs)
    R = 1 inch since that is the length from the center of the shaft that the motor is rated
    p = 1 inch / 13 = .08 inches

    Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
    Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
    Effort = 5 N + (90 N / (15.7))
    Effort = 5 N + (5.73 N)
    Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

    I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

    Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

    With a bit of algebra, the formula can be rewritten to find the load:

    Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

    Another formula that does not consider friction at all:

    Effort = (Load x p) / (2 x pi x R)

    Lets see if we get similar results:

    Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
    Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

    The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

    It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

    Example for a 10 TPI 5 start (2 turns per inch) lead screw:

    Load = 90 N (20.2 lbs)
    R = 1 inch since that is the length from the center of the shaft that the motor is rated
    p = 1 inch / 2 = .5 inches

    Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
    Effort = 5 N + (90 N / (6.28 x 2 x .2))
    Effort = 5 N + (90 N / (2.512))
    Effort = 5 N + (35.83 N)
    Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

    Customer Response:
    thank you so much

    Additional Information:


    Additional Information:


    Additional Information:
    how do i calculate torque of stepper motor if lead screw coupled to motor shaft and load applied by lead screw on plate is 100 kg by vertically

    Additional Information:
    Pls


    Additional Information:
    1m 16mmdiameter ball screws calculations

    Click the link to respond:
    What maximum weight will my motor torque be able to lift? Effort = Sf + (Load/(2 x pi x (R/p) x Se)) In this formula, is Sf (static force) include gravity? how much usually is static force? can you please give one example to calculate max. weight Z-axis can carry?

  • How can i calculate how much can carry my stepper motor? i have these informations: (Detent Torque: 2.2N.cm; Rotor Inertia: 54g.cm2; Holding Torque: 40N.cm). It's a nema 17

    The holding torque will provide the best information for the calculation on how much your stepper motor will carry. But first, when you say carry, do you mean how much weight it can lift, how much inertia it can withstand during an acceleration and deceleration state or how fast it can accelerate or velocity it can maintain under load from the milling process?

    Click the link to respond:
    How can i calculate how much can carry my stepper motor? i have these informations: (Detent Torque: 2.2N.cm; Rotor Inertia: 54g.cm2; Holding Torque: 40N.cm). It's a nema 17

  • How can i calculate how much can carry my stepper motor? i have these informations: (Detent Torque: 2.2N.cm; Rotor Inertia: 54g.cm2; Holding Torque: 40N.cm). It's a nema 17

    The holding torque will provide the best information for the calculation on how much your stepper motor will carry. But first, when you say carry, do you mean how much weight it can lift, how much inertia it can withstand during an acceleration and deceleration state or how fast it can accelerate or velocity it can maintain under load from the milling process?

    Click the link to respond:
    How can i calculate how much can carry my stepper motor? i have these informations: (Detent Torque: 2.2N.cm; Rotor Inertia: 54g.cm2; Holding Torque: 40N.cm). It's a nema 17

  • THE BLACKTOE REQUIRES HOW MUCH MOTOR CABLE

    The motor cables for the blackToe are as follows:

    Total 30 feet

    X - 9
    Y - 10
    Z - 11

    Click the link to respond:
    THE BLACKTOE REQUIRES HOW MUCH MOTOR CABLE

  • Hi what is the maximun weight of a gantry that a Nema 34 651 oz can carry ?

    The holding torque of the NEMA34 motor is rated at 651 oz-in. This is the maximum amount of weight the motor holds in a stationary position while optimal current is being applied through the driver. This is equivalent to 40.68 lbs per inch. Torque is measured from the center of the shaft. The torque applied to the shaft moving 1 inch is inversely proportional. For example: Moving 1/2" on the shaft has a maximum of 1302 oz or moving 2" has a maximum of 325.5 oz.

    Click the link to respond:
    Hi what is the maximun weight of a gantry that a Nema 34 651 oz can carry ?

  • HOW MUCH MOTOR CABLE DO I NEED FOR A BLACKFOOT

    The blackfoot requires a total of 50 feet of cable.

    The X axis needs 15 feet
    The Y axis needs 17 feet
    and the Z-axis needs 18 feet

    These are 20 gauge 4 conductor cable.

    Click the link to respond:
    HOW MUCH MOTOR CABLE DO I NEED FOR A BLACKFOOT

  • HOW DO I DETERMINE THE AMOUNT OF SCREW WEIGTH THAT MY MOTOR CAN HANDLE

    There are two main questions that we can answer with respect to motor torque and the mechanical advantage of lead screws, 1) What torque motor do you need to lift a particular weight, or 2) What maximum weight will my motor torque be able to lift.

    This formula uses Newtons (N) as it's final unit. Use this with the included radius (R) to determine the torque. Newtons can easily be converted to lbs or ounces using online conversions.

    Effort = Sf + (Load/(2 x pi x (R/p) x Se))

    where:
    p = pitch of the screw
    Se = screw efficiency = Standard lead screw will be between 20% (.2) and 40% (.4)
    Sf = static force. This is the force that is needed to start the movement. The number may be eliminated, but it is good to use a number in the 5 N to 20 N range.
    Load = the expected load that the effort will need to carry (i.e., the router and the included axis assembly that the motor will need to lift)
    R = radius of the lead screw


    This formula is based on the "law of the machine"

    The final effort amount with its unit of newtons and R will be the torque. For example, if the effort comes to 100 N (newtons) and the R is .5 inches, then you can assume that the effort is 50 N-in since it would take twice the effort to turn form the one inch mark from the center of the shaft.

    Example:

    Load = 90 N (20.2 lbs)
    R = 1 inch since that is the length from the center of the shaft that the motor is rated
    p = 1 inch / 13 = .08 inches

    Effort = 5 N + (90 N / (2 x 3.14 x (1 / .08) x .2))
    Effort = 5 N + (90 N / (6.28 x 12.5 x .2))
    Effort = 5 N + (90 N / (15.7))
    Effort = 5 N + (5.73 N)
    Effort = 10.7 N = 2.4 lbs = 38.4 oz-in

    I am putting the oz-in on the end because the formula considers the distance from the center of the shaft to be one inch.

    Therefore, a 425 oz-in motor would be able to lift a 20.2 lb Router with its accompanying assembly. If the assembly and router is heavier, plug in the numbers and determine the effort required.

    With a bit of algebra, the formula can be rewritten to find the load:

    Load = (Effort - Sf) x (2 x pi x (R/p) x Se)

    Another formula that does not consider friction at all:

    Effort = (Load x p) / (2 x pi x R)

    Lets see if we get similar results:

    Effort = (20 lb x .08 inches) / (2 x 3.14 x 1)
    Effort = 1.6 / 6.28 = .255 lbs = 4.08 oz-in

    The results from both formulas appear to be very small because a 13 TPI screw will have enormous mechanical advantage.

    It is evident that the first formula that does consider friction that we are loosely estimating is far more conservative than the second formula. Either way, even the most conservative formula shows that the 425 oz-in motor will handle very large weights. If you are using a lead screw with only two turns per inch, .5 inch pitch, you can determine the requirements with the first formula.

    Example for a 10 TPI 5 start (2 turns per inch) lead screw:

    Load = 90 N (20.2 lbs)
    R = 1 inch since that is the length from the center of the shaft that the motor is rated
    p = 1 inch / 2 = .5 inches

    Effort = 5 N + (90 N / (2 x 3.14 x (1 / .5) x .2))
    Effort = 5 N + (90 N / (6.28 x 2 x .2))
    Effort = 5 N + (90 N / (2.512))
    Effort = 5 N + (35.83 N)
    Effort = 40.828 N = 9.18 lbs = 146.88 oz-in

    Customer Response:
    thank you so much

    Additional Information:


    Additional Information:


    Additional Information:
    how do i calculate torque of stepper motor if lead screw coupled to motor shaft and load applied by lead screw on plate is 100 kg by vertically

    Additional Information:
    Pls


    Additional Information:
    1m 16mmdiameter ball screws calculations

    Click the link to respond:
    HOW DO I DETERMINE THE AMOUNT OF SCREW WEIGTH THAT MY MOTOR CAN HANDLE

  • HOW MUCH MOTOR CABLE SHOULD PURCHASE FOR THE BLUECHICK

    The recommended total length of motor cable should be 15 feet for the blueChick v4.2

    Z - 6 feet
    Y - 5 feet
    X- 4 feet

    20 AWG 4 conductor

    If your drivers will be positioned farther from the machine, you may need longer cable.

    Click the link to respond:
    HOW MUCH MOTOR CABLE SHOULD PURCHASE FOR THE BLUECHICK

  • How can I determine which wires on my stepper motor bellong to A+ A- B+ or B-?

    You can use a multimeter to determine the wires of the same coil (i.e A+ and A- belong to he same coil). The wires that are connected on the same coil will have relatively low resistance. A wire from one coil to another coil with have no continuity since the two coils are not touching each other.

    Click the link to respond:
    How can I determine which wires on my stepper motor bellong to A+ A- B+ or B-?

  • HOW MUCH MOTOR CABLE FOR THE BLACKFOOT?

    The motor cables for the blackToe are as follows:

    Total 30 feet

    X - 9
    Y - 10
    Z - 11

    Click the link to respond:
    HOW MUCH MOTOR CABLE FOR THE BLACKFOOT?

  • How can I have two stepper motors on one axis

    Yes, you can use 2 motors in the same axis output, however you will still need a driver for that motor! Also depending on the orientation on which you mount the motor you might have to invert the direction of the motor, and that will be simple by swapping the A+,A-, to the B+,B- locations and vice versa, from the driver to the motor wiring.

    Also you can run a slave motor using another axis on the board, and setting it up in the Planet-CNC settings.

    Planet-CNC/File/Settings/Axes, here you will enter 3 in the Number of Axes location, and then change the Function of the Axis 4 to Slave 1. There you will have the 4th axis or A-axis be a slave for the x-axis.
    Slave 1 - X-Axis
    Slave 2 - Y-Axis
    Slave 3 - A-Axis
    Slave 4 - B-Axis
    Etc...

    Click the link to respond:
    How can I have two stepper motors on one axis

  • How do I connect my motor wires to the driver?

    Use the datasheet associated to the motor that you purchased. Use the bipolar parallel configuration to optimum performance. The datasheets are located in their respective motor product pages. Just click on the motion electronics at the left and scroll down to the motor you have and click on the title, or datasheet link next to the motor. The datasheet will either be in the form of a pdf, or within the instructions on that product page.

    Additional Information:
    wiring diagram

    Click the link to respond:
    How do I connect my motor wires to the driver?

  • HOW DO I SET UP MY MOTOR DRIVERS?

    blueChick:

    X-axis
    “CW230 (3.0A) Driver”
    Set to 1/16 Microstep, 2.7A
    Dipswitches: 11001100
    Mach3 Motor Tuning: 1422.22 steps/in

    Y-axis
    “CW230 (3.0A) Driver”
    Set to 1/16 Microstep, 2.7A
    Dipswitches: 11001100
    Mach3 Motor Tuning: 1422.22 steps/in

    Z-axis
    “CW230 (3.0A) Driver”
    Set to 1/4 Microstep, 2.7A
    Dipswitches: 10101100
    Mach3 Motor Tuning: 1600 steps/in

    blackToe:

    X-axis
    “CW230 (3.0A) Driver”
    Set to 1/16 Microstep, 2.7A
    Dipswitches: 11001100
    Mach3 Motor Tuning: 1422.22 steps/in

    Y-axis
    “CW230 (3.0A) Driver”
    Set to 1/16 Microstep, 2.7A
    Dipswitches: 11001100
    Mach3 Motor Tuning: 1422.22 steps/in

    Z-axis
    “CW230 (3.0A) Driver”
    Set to 1/4 Microstep, 2.7A
    Dipswitches: 10101100
    Mach3 Motor Tuning: 1600 steps/in

    blackFoot:

    X-axis
    “CW8060 (6.0A) Driver”
    Set to 1/16 Microstep, 2.7A
    Dipswitches: 11001100 (“0”=down, “1”=up)
    Mach3 Motor Tuning: 914.29 steps/in

    Y-axis
    “CW230 (3.0A) Driver”
    Set to 1/16 Microstep, 2.7A
    Dipswitches: 11001100
    Mach3 Motor Tuning: 1422.22 steps/in

    Z-axis
    “CW230 (3.0A) Driver”
    Set to 1/4 Microstep, 2.7A
    Dipswitches: 10101100
    Mach3 Motor Tuning: 1600 steps/in

    greenBull:

    X-axis
    “CW8060 (6.0A) Driver”
    Set to 5.43A, 1/16 Microstep
    Dipswitches: 01100110 (“0”=down, “1”=up)
    Mach3 Motor Tuning: 914.29 steps/in

    Y-axis
    “CW8060 (6.0A) Driver”
    Set to 5.43A, 1/16 Microstep
    Dipswitches: 01100110
    Mach3 Motor Tuning: 914.29 steps/in

    Z-axis
    “CW8060 (6.0A) Driver”
    Set to 5.43A, 1/4 Microstep
    Dipswitches: 01100100
    Mach3 Motor Tuning: 1600 steps/in

    Click the link to respond:
    HOW DO I SET UP MY MOTOR DRIVERS?

  • ok I Build my CNC machine table and now need a complete set for motor and software how you can help me

    Yes, I will need to know more specifics of the machine so I can recommend the correct electronics.

    Click the link to respond:
    ok I Build my CNC machine table and now need a complete set for motor and software how you can help me

  • Can I drive my X axes with 2 motors using one motor driver?

    It is not recommended to drive two stepping (stepper) motors with a single driver. The driver will need to output the sum of the current that is rated for both motors. The best way to drive two motors on the same axis, or if you need the motors to spin in a synchronous fashion, then have each motor connected to their own driver and connect the signal wires from the drivers to the same signal step and direction pin on the breakout/interface board.

    Click the link to respond:
    Can I drive my X axes with 2 motors using one motor driver?

  • How do I wire two motors on the same axis?

    Yes, you can use 2 motors in the same axis output, however you will still need a driver for that stepper motor. Also depending on the orientation on which you mount the motor you might have to invert the direction of the motor, and that will be simple by swapping the A+,A-, to the B+,B- locations and vice versa, from the driver to the motor wiring.

    The wiring scheme would look like this:
    The step and direction output terminals on the CNC controller interface for the axis you want to have two motors would connect to both drivers of the two stepper motors on that axis.

    Additional Information:
    I have been running two motors from the same driver for 10 years on my 3m x 1.6m router. Both motors driving the gantry are wired together. I see no reason to use two drivers. The motors are high torque Nema 34. I've had no issues.

    Click the link to respond:
    How do I wire two motors on the same axis?

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